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TMUA 2017 · Paper 2 · Question 4 of 20

TMUA 2017 Paper 2 Question 4

Trigonometry — Judging a student's trigonometric reasoning. Try it first; the answer and a full worked solution are below.

TMUA 2017 · Paper 2TrigonometryJudging a student's trigonometric reasoning5 options
The following question appeared in an examination:

Given that tanx=3, find the possible values of sin 2x.

A student gave the following answer:

tanx=3 so x= 60 and 2x= 120,
therefore sin 2x=32.

Which one of the following statements is correct?

  1. A32 is the only possible value, and this is fully supported by the reasoning given in the student's answer.
  2. B32 is the only possible value, but the reasoning given should consider other possible values of x for which tanx=3.
  3. C32 is the only possible value, but the reasoning given should consider other possible values of x for which sin 2x=32.
  4. D32 is not the only possible value because the reasoning given should have considered other possible values of x for which tanx=3.
  5. E32 is not the only possible value because the reasoning given should have considered other possible values of x for which sin 2x=32.
Show the answer and worked solution
answer · B
  1. A32 is the only possible value, and this is fully supported by the reasoning given in the student's answer.
  2. B32 is the only possible value, but the reasoning given should consider other possible values of x for which tanx=3.
  3. C32 is the only possible value, but the reasoning given should consider other possible values of x for which sin 2x=32.
  4. D32 is not the only possible value because the reasoning given should have considered other possible values of x for which tanx=3.
  5. E32 is not the only possible value because the reasoning given should have considered other possible values of x for which sin 2x=32.
The student picked one solution of tanx=3 without saying why the others do not matter, so the reasoning is incomplete. Checking them: tan has period 180, so x= 60+ 180n, and doubling gives 2x= 120+ 360n, which is the same angle every time. So sin 2x=32 really is the only value — the answer is right but the argument needs the extra step of ruling the other values of x out.