TTMUA Lab
TMUA 2017 · Paper 2 · Question 4 of 20

TMUA 2017 Paper 2 Question 4

Trigonometry — Judging a student's trigonometric reasoning. Try it first; the answer and a full worked solution are below.

TMUA 2017 · Paper 2TrigonometryJudging a student's trigonometric reasoning5 options
The following question appeared in an examination:

Given that tan x = √3, find the possible values of sin 2x.

A student gave the following answer:

tan x = √3 so x = 60∘ and 2x = 120∘,
therefore sin 2x = √32.

Which one of the following statements is correct?

  1. A√32 is the only possible value, and this is fully supported by the reasoning given in the student's answer.
  2. B√32 is the only possible value, but the reasoning given should consider other possible values of x for which tan x = √3.
  3. C√32 is the only possible value, but the reasoning given should consider other possible values of x for which sin 2x = √32.
  4. D√32 is not the only possible value because the reasoning given should have considered other possible values of x for which tan x = √3.
  5. E√32 is not the only possible value because the reasoning given should have considered other possible values of x for which sin 2x = √32.
Show the answer and worked solution
answer · B
  1. A√32 is the only possible value, and this is fully supported by the reasoning given in the student's answer.
  2. B√32 is the only possible value, but the reasoning given should consider other possible values of x for which tan x = √3.
  3. C√32 is the only possible value, but the reasoning given should consider other possible values of x for which sin 2x = √32.
  4. D√32 is not the only possible value because the reasoning given should have considered other possible values of x for which tan x = √3.
  5. E√32 is not the only possible value because the reasoning given should have considered other possible values of x for which sin 2x = √32.
The student picked one solution of tan x = √3 without saying why the others do not matter, so the reasoning is incomplete. Checking them: tan has period 180∘, so x = 60∘ + 180∘ n, and doubling gives 2x = 120∘ + 360∘ n, which is the same angle every time. So sin 2x = √32 really is the only value — the answer is right but the argument needs the extra step of ruling the other values of x out.