Which one of the following is a sufficient condition for the equation x3 − 3x2 + a = 0, where a is a constant, to have exactly one real root?
- Aa > 0
- Ba ≤ 0
- Ca ≥ 4
- Da < 4
- E|a| > 4
- F|a| ≤ 4
- Ga = 94
- H|a| = 32
Show the answer and worked solution
answer · E
- Aa > 0
- Ba ≤ 0
- Ca ≥ 4
- Da < 4
- E|a| > 4
- F|a| ≤ 4
- Ga = 94
- H|a| = 32
Let y = x3 − 3x2 + a. Then dydx = 3x2 − 6x = 3x(x−2), giving a local maximum at x = 0 with value a and a local minimum at x = 2 with value a − 4. A cubic has exactly one real root precisely when those two stationary values have the same sign, that is a(a−4) > 0, so a < 0 or a > 4. Now check the options: |a| > 4 means a > 4 or a < −4, and both lie inside that region, so it is sufficient. The near misses fail at their endpoints — a = 0 gives x2(x−3) and a = 4 gives (x+1)(x−2)2, each with two distinct real roots.