The positive real numbers a × 10−3, b × 10−2 and c × 10−1 are each in standard form, and (a × 10−3) + (b × 10−2) = (c × 10−1). Which of the following statements (I, II, III, IV) must be true?
I a > 9
II b > 9
III a < c
IV b < c
- AI only
- BII only
- CI and II only
- DI and III only
- EI and IV only
- FII and III only
- GII and IV only
- HI, II, III and IV
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answer · B
- AI only
- BII only
- CI and II only
- DI and III only
- EI and IV only
- FII and III only
- GII and IV only
- HI, II, III and IV
Standard form means 1 ≤ a, b, c < 10. Multiplying the equation by 103 gives a + 10b = 100c. Since c ≥ 1, the left side is at least 100, and since a < 10 this forces 10b > 90, so b > 9: statement II must hold. Nothing similar pins down a — take c = 1, b = 9.5, a = 5, which satisfies everything while a > 9 and a < c both fail. And IV is never true, since b > 9 while c < 10 forces c < 1.1.