Consider the equation 2x = mx + c, where m and c are real constants.
Which of the following statements is/are true?
I The equation has a negative real solution only if c > 1.
II The equation has two distinct real solutions if c > 1.
III The equation has two distinct positive real solutions if and only if c ≤ 1.
- Anone of them
- BI only
- CII only
- DIII only
- EI and II only
- FI and III only
- GII and III only
- HI, II and III
Show the answer and worked solution
answer · A
- Anone of them
- BI only
- CII only
- DIII only
- EI and II only
- FI and III only
- GII and III only
- HI, II and III
All three can be knocked down by taking m = 0, which makes the right-hand side a horizontal line. With m = 0 and c = 12 the equation 2x = 12 has the negative solution x = −1 even though c ≤ 1, so I fails. With m = 0 and c = 2 the equation 2x = 2 has the single solution x = 1, so c > 1 does not force two solutions and II fails. With m = 0 and c = 0 the equation 2x = 0 has no solutions at all, yet c ≤ 1, so the "if" half of III fails. None of them.