Evaluate ∫916(1√x + √x)2 dx − ∫916(1√x − √x)2 dx
- A0
- B2
- C4
- D7
- E14
- F28
- G75
- H175
Show the answer and worked solution
answer · F
- A0
- B2
- C4
- D7
- E14
- F28
- G75
- H175
Combine the integrals before doing any work. With a = 1√ x and b = √ x, the integrand is (a+b)2 − (a−b)2 = 4ab = 4⋅1√ x⋅√ x = 4. So the value is ∫916 4 dx = 4(16−9) = 28.