Here is an attempt to solve the inequality x4 − 2x2 − 3 < 0 by completing the square:
x4 − 2x2 − 3 < 0
I if and only if x4 − 2x2 + 1 < 4
II if and only if (x2 − 1)2 < 4
III if and only if −2 < x2 − 1 < 2
IV if and only if x2 − 1 < 2
V if and only if x2 < 3
VI if and only if −√3 < x < √3
Which of the following statements is true?
- AThe argument is completely correct.
- BThe first error occurs in line I.
- CThe first error occurs in line II.
- DThe first error occurs in line III.
- EThe first error occurs in line IV.
- FThe first error occurs in line V.
- GThe first error occurs in line VI.
Show the answer and worked solution
answer · A
- AThe argument is completely correct.
- BThe first error occurs in line I.
- CThe first error occurs in line II.
- DThe first error occurs in line III.
- EThe first error occurs in line IV.
- FThe first error occurs in line V.
- GThe first error occurs in line VI.
Every step holds. Adding 4 to both sides gives line I, and the left side factorises as (x2−1)2 for line II. Line III is the standard unpacking of |x2 − 1| < 2. Line IV looks like it discards information, but it does not: x2 ≥ 0 forces x2 − 1 ≥ −1 > −2, so the left-hand inequality is automatic. Lines V and VI then follow directly.