How many solutions are there to (1 + 3cos 3θ)2 = 4 in the interval 0∘ ≤ θ ≤ 180∘?
- A1
- B2
- C3
- D4
- E5
- F6
Show the answer and worked solution
answer · E
- A1
- B2
- C3
- D4
- E5
- F6
Taking square roots, 1 + 3cos 3θ = ± 2, so cos 3θ = 13 or cos 3θ = −1. As θ runs over [0∘, 180∘], 3θ runs over [0∘, 540∘]. In that range cos u = −1 at u = 180∘ and 540∘ — two solutions — while cos u = 13 has one solution in each of [0∘, 180∘], [180∘, 360∘] and [360∘, 540∘] — three more. That is 5 in total.