Point P lies on the circle with equation (x−2)2 + (y−1)2 = 16.
Point Q lies on the circle with equation (x−4)2 + (y+5)2 = 16.
What is the maximum possible length of PQ?
- A10
- B14
- C16
- D2√34
- E10√2
- F8 + 2√10
- G16 + 2√6
Show the answer and worked solution
answer · F
- A10
- B14
- C16
- D2√34
- E10√2
- F8 + 2√10
- G16 + 2√6
The centres are (2, 1) and (4, −5), a distance √22 + 62 = √40 = 2√10 apart, and both radii are 4. The greatest separation puts P and Q at opposite ends of the line through the centres, giving 2√10 + 4 + 4 = 8 + 2√10.