A triangle XYZ is called fun if it has the following properties: angle YXZ = 30∘ XY = √3 a YZ = a where a is a constant.
For a given value of a, there are two distinct fun triangles S and T, where the area of S is greater than the area of T.
Find the ratio area of S : area of T.
- A1 : 1
- B2 : 1
- C2 : √3
- D√3 : 1
- E3 : 1
Show the answer and worked solution
answer · B
- A1 : 1
- B2 : 1
- C2 : √3
- D√3 : 1
- E3 : 1
YZ is opposite the 30∘ angle, so the sine rule gives asin 30∘ = √3 asin Z and sin Z = √32. Hence Z = 60∘ or Z = 120∘ — the ambiguous case — leaving Y = 90∘ or Y = 30∘. Using XZsin Y = asin 30∘ gives XZ = 2a in the first case and XZ = a in the second. The areas are 12(√3 a)(2a)sin 30∘ = √32a2 and 12(√3 a)(a)sin 30∘ = √34a2, a ratio of 2 : 1.