Consider the following two statements about the polynomial f(x):
P: f(x) = 0 for exactly three real values of x
Q: f'(x) = 0 for exactly two real values of x
Which one of the following is correct?
- AP is necessary but not sufficient for Q.
- BP is sufficient but not necessary for Q.
- CP is necessary and sufficient for Q.
- DP is not necessary and not sufficient for Q.
Show the answer and worked solution
answer · D
- AP is necessary but not sufficient for Q.
- BP is sufficient but not necessary for Q.
- CP is necessary and sufficient for Q.
- DP is not necessary and not sufficient for Q.
The cubic case makes both directions look plausible, so the work is in finding polynomials that break each one. For P not sufficient, take f(x) = x4 − x2 = x2(x−1)(x+1): it vanishes at exactly three values −1, 0, 1, but f'(x) = 4x3 − 2x vanishes at three values, not two. For P not necessary, take f(x) = x3 − 3x + 10: f'(x) = 3x2 − 3 vanishes at exactly two values, yet f has a positive minimum (f(1) = 8) so only one real root. Neither implication holds.