Find the complete set of values of the constant c for which the cubic equation 2x3 − 3x2 − 12x + c = 0 has three distinct real solutions.
- A−20 < c < 7
- B−7 < c < 20
- Cc > 7
- Dc > −7
- Ec < 20
- Fc < −20
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answer · B
- A−20 < c < 7
- B−7 < c < 20
- Cc > 7
- Dc > −7
- Ec < 20
- Fc < −20
Write f(x) = 2x3 − 3x2 − 12x + c. Then f'(x) = 6x2 − 6x − 12 = 6(x − 2)(x + 1), so the turning points are at x = −1 and x = 2; the positive leading coefficient makes x = −1 the local maximum and x = 2 the local minimum. Three distinct roots need the curve to cross the axis on both sides of each turning point, that is f(−1) > 0 and f(2) < 0. Since f(−1) = 7 + c and f(2) = −20 + c, this gives −7 < c < 20.