A circle has equation x2 + y2 − 18x − 22y + 178 = 0 A regular hexagon is drawn inside this circle so that the vertices of the hexagon touch the circle.
What is the area of the hexagon?
- A6
- B6√3
- C18
- D18√3
- E36
- F36√3
- G48
- H48√3
Show the answer and worked solution
answer · F
- A6
- B6√3
- C18
- D18√3
- E36
- F36√3
- G48
- H48√3
Complete the square: (x−9)2 + (y−11)2 = 81 + 121 − 178 = 24, so r2 = 24. A regular hexagon inscribed in a circle of radius r splits into six equilateral triangles of side r, so its area is 6 × √34r2 = 3√32r2. With r2 = 24 that is 36√3. Note that only r2 is needed, so there is no reason to simplify √24.