The graph of y = log10 x is translated in the positive y-direction by 2 units.
This translation is equivalent to a stretch of factor k parallel to the x-axis.
What is the value of k?
- A0.01
- Blog10 2
- C0.5
- D2
- Elog2 10
- F100
Show the answer and worked solution
answer · A
- A0.01
- Blog10 2
- C0.5
- D2
- Elog2 10
- F100
The translated curve is y = log10 x + 2 = log10(100x). A stretch of factor k parallel to the x-axis replaces x by xk, giving y = log10xk. Matching the two, 1k = 100, so k = 0.01. The stretch is a squash towards the y-axis, which is why the answer is small rather than 100.