The functions f and g are given by f(x) = 3x2 + 12x + 4 and g(x) = x3 + 6x2 + 9x − 8.
What is the complete set of values of x for which one of the functions is increasing and the other decreasing?
- Ax ≥ −1
- Bx ≤ −1
- C−3 ≤ x ≤ −2, x ≥ −1
- Dx ≤ −2, x ≥ −1
- Ex ≤ −3, −2 ≤ x ≤ −1
- Fx ≤ −3, x ≥ −2
- G−2 ≤ x ≤ −1
Show the answer and worked solution
answer · E
- Ax ≥ −1
- Bx ≤ −1
- C−3 ≤ x ≤ −2, x ≥ −1
- Dx ≤ −2, x ≥ −1
- Ex ≤ −3, −2 ≤ x ≤ −1
- Fx ≤ −3, x ≥ −2
- G−2 ≤ x ≤ −1
Find where each derivative is positive. f'(x) = 6x + 12, so f increases for x ≥ −2 and decreases for x ≤ −2. g'(x) = 3x2 + 12x + 9 = 3(x+1)(x+3), so g increases for x ≤ −3 and for x ≥ −1, and decreases on −3 ≤ x ≤ −1. Now take the two cases. With f increasing and g decreasing: x ≥ −2 and −3 ≤ x ≤ −1, giving −2 ≤ x ≤ −1. With f decreasing and g increasing: x ≤ −2 together with x ≤ −3 or x ≥ −1, giving x ≤ −3.