Which one of the following is a necessary and sufficient condition for ∑k=1nsin(kπ3) = √32 to be true?
- An = 1
- Bn is a multiple of 3
- Cn is a multiple of 6
- Dn is 1 more than a multiple of 3
- En is 1 more than a multiple of 6
- Fn is 1 more than a multiple of 6 or n is 2 more than a multiple of 6
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answer · D
- An = 1
- Bn is a multiple of 3
- Cn is a multiple of 6
- Dn is 1 more than a multiple of 3
- En is 1 more than a multiple of 6
- Fn is 1 more than a multiple of 6 or n is 2 more than a multiple of 6
The terms repeat with period 6: for k = 1, 2, 3, 4, 5, 6 they are √32, √32, 0, −√32, −√32, 0, and each block of six sums to zero. So work out the running totals across one block: S1 = √32, S2 = √3, S3 = √3, S4 = √32, S5 = 0, S6 = 0, and then the pattern repeats exactly. The value √32 occurs at n ≡ 1 and n ≡ 4 modulo 6, and those two residues together are precisely n ≡ 1 modulo 3. Stopping at n = 1 or at n ≡ 1 modulo 6 gives a sufficient but not necessary condition.