Which one of A–F correctly completes the following statement?
Given that a < b, and f(x) > 0 for all x with a < x < b, the trapezium rule produces an overestimate for ∫ab f(x) dx …
- A… if f'(x) > 0 and f''(x) < 0 for all x with a < x < b
- B… only if f'(x) > 0 and f''(x) < 0 for all x with a < x < b
- C… if and only if f'(x) > 0 and f''(x) < 0 for all x with a < x < b
- D… if f'(x) < 0 and f''(x) > 0 for all x with a < x < b
- E… only if f'(x) < 0 and f''(x) > 0 for all x with a < x < b
- F… if and only if f'(x) < 0 and f''(x) > 0 for all x with a < x < b
Show the answer and worked solution
answer · D
- A… if f'(x) > 0 and f''(x) < 0 for all x with a < x < b
- B… only if f'(x) > 0 and f''(x) < 0 for all x with a < x < b
- C… if and only if f'(x) > 0 and f''(x) < 0 for all x with a < x < b
- D… if f'(x) < 0 and f''(x) > 0 for all x with a < x < b
- E… only if f'(x) < 0 and f''(x) > 0 for all x with a < x < b
- F… if and only if f'(x) < 0 and f''(x) > 0 for all x with a < x < b
What controls the trapezium rule is the second derivative alone: each chord lies above a curve that bends upwards, so f''(x) > 0 throughout gives an overestimate, and f''(x) < 0 gives an underestimate. Whether the function is increasing or decreasing is irrelevant. So any option with f'' < 0 is wrong, ruling out A, B and C. Between the remaining three, f' < 0 and f'' > 0 is enough to guarantee an overestimate, so "if" is correct. It is not "only if": f(x) = ex on [0, 1] is increasing and convex and still overestimated, so the condition is not necessary, and E and F fail.