The curve S has equation y = px2 + 6x − q where p and q are constants.
S has a line of symmetry at x = −14 and touches the x-axis at exactly one point.
What is the value of p + 8q?
- A6
- B18
- C21
- D25
- E38
Show the answer and worked solution
answer · A
- A6
- B18
- C21
- D25
- E38
The axis of symmetry of px2 + 6x − q sits at x = −62p = −3p, so −3p = −14 and p = 12. Touching the x-axis once means a repeated root, so the discriminant vanishes: 62 − 4p(−q) = 36 + 4pq = 0. With p = 12 this gives 48q = −36, so q = −34. Then p + 8q = 12 − 6 = 6.