TTMUA Lab
TMUA 2020 · Paper 1 · Question 20 of 20

TMUA 2020 Paper 1 Question 20

Algebra and functions — Repeated roots · counting parameter values. Try it first; the answer and a full worked solution are below.

TMUA 2020 · Paper 1Algebra and functionsRepeated roots · counting parameter values6 optionshard
For how many values of a is the equation (xa)(x2x+a)= 0 satisfied by exactly two distinct values of x?
  1. A0
  2. B1
  3. C2
  4. D3
  5. E4
  6. Fmore than 4
Show the answer and worked solution
answer · C
  1. A0
  2. B1
  3. C2
  4. D3
  5. E4
  6. Fmore than 4
One root is always x=a; the rest come from x2x+a= 0, whose discriminant is 1  4a. If 1  4a< 0 there is only the single root x=a, so exactly two distinct roots can happen in only two ways. Either the quadratic has a repeated root distinct from a: 1  4a= 0 gives a=14, with repeated root x=1214, so the roots are 14 and 12 — that works. Or the quadratic has two distinct roots, one of which is a: substituting x=a gives a2a+a=a2= 0, so a= 0, and then the roots are 0 and 1 — that works too. That is 2 values of a.