For how many values of a is the equation (x − a)(x2 − x + a) = 0 satisfied by exactly two distinct values of x?
- A0
- B1
- C2
- D3
- E4
- Fmore than 4
Show the answer and worked solution
answer · C
- A0
- B1
- C2
- D3
- E4
- Fmore than 4
One root is always x = a; the rest come from x2 − x + a = 0, whose discriminant is 1 − 4a. If 1 − 4a < 0 there is only the single root x = a, so exactly two distinct roots can happen in only two ways. Either the quadratic has a repeated root distinct from a: 1 − 4a = 0 gives a = 14, with repeated root x = 12 ≠ 14, so the roots are 14 and 12 — that works. Or the quadratic has two distinct roots, one of which is a: substituting x = a gives a2 − a + a = a2 = 0, so a = 0, and then the roots are 0 and 1 — that works too. That is 2 values of a.