S is a geometric sequence.
The sum of the first 6 terms of S is equal to 9 times the sum of the first 3 terms of S.
The 7th term of S is 360.
Find the 1st term of S.
- A4027
- B409
- C403
- D4516
- E458
- F454
Show the answer and worked solution
answer · E
- A4027
- B409
- C403
- D4516
- E458
- F454
Split the first six terms into the first three plus the next three: the second block is the first block multiplied by r3, so S6 = S3(1 + r3). The condition S6 = 9S3 then gives 1 + r3 = 9, so r3 = 8 and r = 2. (The alternative r = 1 from the algebraic route fails, since it gives S6 = 2S3.) The seventh term is ar6 = 64a = 360, so a = 36064 = 458.