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TMUA 2019 · Paper 1 · Question 19 of 20

TMUA 2019 Paper 1 Question 19

Trigonometry — Summing a periodic trigonometric series. Try it first; the answer and a full worked solution are below.

TMUA 2019 · Paper 1TrigonometrySumming a periodic trigonometric series6 options
Find the value of k=090sin(10 + 90k)
  1. A0
  2. Bsin 10
  3. Csin 100
  4. Dsin 190
  5. Esin 280
  6. F1
Show the answer and worked solution
answer · C
  1. A0
  2. Bsin 10
  3. Csin 100
  4. Dsin 190
  5. Esin 280
  6. F1
The terms repeat with period 4 in k: sin 10, sin 100, sin 190=sin 10, sin 280=sin 100, and each block of four sums to zero. There are 91 terms, and 91 = 4 × 22 + 3, so the 88 terms with k= 0 to 87 cancel completely and only k= 88,  89,  90 survive. Those are sin 10+sin 100+sin 190=sin 10+sin 100sin 10=sin 100.