f(x) is a polynomial with real coefficients.
The equation f(x) = 0 has exactly two real roots, x = −p and x = p, where p > 0.
Consider the following three statements:
1 f'(x) = 0 for exactly one value of x between −p and p
2 The area between the curve y = f(x), the x-axis and the lines x = −p and x = p is given by 2∫0p f(x) dx
3 The graph of y = −f(−x) intersects the x-axis at the points x = −p and x = p only
Which of the above statements must be true?
- Anone
- B1 only
- C2 only
- D3 only
- E1 and 2 only
- F1 and 3 only
- G2 and 3 only
- H1, 2 and 3
Show the answer and worked solution
answer · D
- Anone
- B1 only
- C2 only
- D3 only
- E1 and 2 only
- F1 and 3 only
- G2 and 3 only
- H1, 2 and 3
Rolle's theorem guarantees at least one stationary point between the roots, not exactly one. Take f(x) = (x2 − p2)(x2 + ε) with ε small and positive: it still has only ± p as real roots, but f'(x) = 2x(2x2 + ε − p2) vanishes three times inside, so statement 1 fails. Statement 2 assumes f is even and of constant sign, neither of which is given. Statement 3 is safe: −f(−x) = 0 exactly when f(−x) = 0, that is when −x = ± p, so the roots are again ± p and nothing else.