Consider the statement (×) about a real number x:
(×) There exists a real number y such that x − xy + y is negative.
For how many real values of x is (×) true?
- Ano values of x
- Bexactly one value of x
- Cexactly two values of x
- Dall except exactly two values of x
- Eall except exactly one value of x
- Fall values of x
Show the answer and worked solution
answer · E
- Ano values of x
- Bexactly one value of x
- Cexactly two values of x
- Dall except exactly two values of x
- Eall except exactly one value of x
- Fall values of x
Group the y terms: x − xy + y = x + y(1 − x). If x ≠ 1 the coefficient 1 − x is non-zero, so y can be chosen to drive the expression as negative as we like. If x = 1 the expression collapses to 1, which is never negative. So (×) holds for every real x except that one value.