A family of quadratic curves is given by yk = 2(x − k2)2 + k22 + 4k + 3 where k is any real number and yk is a function of x.
All these curves are sketched, and the point with the lowest y-coordinate among all the curves yk is (a, b).
Find the value of a + b.
- A−1
- B−3
- C−5
- D−7
- E−9
Show the answer and worked solution
answer · D
- A−1
- B−3
- C−5
- D−7
- E−9
For a fixed k the curve is least at x = k2, where y = k22 + 4k + 3. Minimising that over k: its derivative is k + 4, zero at k = −4, giving y = 8 − 16 + 3 = −5 at x = −2. So (a, b) = (−2, −5) and a + b = −7.