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TMUA 2016 · Paper 1 · Question 18 of 20

TMUA 2016 Paper 1 Question 18

Differentiation and integration — Differentiating a fractional power · where a function decreases. Try it first; the answer and a full worked solution are below.

TMUA 2016 · Paper 1Differentiation and integrationDifferentiating a fractional power · where a function decreases6 options
The function 1x3x2 is defined for all x 0.

The complete set of values of x for which the function is decreasing is

  1. Ax2, x> 0
  2. B2 x< 0
  3. Cx 1, x 0
  4. Dx 1
  5. E2 x 1, x 0
  6. Fx2, x 1
Show the answer and worked solution
answer · A
  1. Ax2, x> 0
  2. B2 x< 0
  3. Cx 1, x 0
  4. Dx 1
  5. E2 x 1, x 0
  6. Fx2, x 1
Split the fraction into powers before differentiating: f(x)=x2/3x1/3, so f'(x)=23x5/313x2/3=x+23x5/3. The sign of x5/3 follows the sign of x, so consider three regions. For x> 0 both x+ 2 and x5/3 are positive, so f' < 0 and the function decreases. For 2 <x< 0 the numerator is positive but x5/3 is negative, making f' > 0. For x<2 both are negative, so f' < 0 again. The complete set is x2 together with x> 0.