The function 1−x3√x2 is defined for all x ≠ 0.
The complete set of values of x for which the function is decreasing is
- Ax ≤ −2, x > 0
- B−2 ≤ x < 0
- Cx ≤ 1, x ≠ 0
- Dx ≥ 1
- E−2 ≤ x ≤ 1, x ≠ 0
- Fx ≤ −2, x ≥ 1
Show the answer and worked solution
answer · A
- Ax ≤ −2, x > 0
- B−2 ≤ x < 0
- Cx ≤ 1, x ≠ 0
- Dx ≥ 1
- E−2 ≤ x ≤ 1, x ≠ 0
- Fx ≤ −2, x ≥ 1
Split the fraction into powers before differentiating: f(x) = x−2/3 − x1/3, so f'(x) = −23 x−5/3 − 13 x−2/3 = −x+23x5/3. The sign of x5/3 follows the sign of x, so consider three regions. For x > 0 both x + 2 and x5/3 are positive, so f' < 0 and the function decreases. For −2 < x < 0 the numerator is positive but x5/3 is negative, making f' > 0. For x < −2 both are negative, so f' < 0 again. The complete set is x ≤ −2 together with x > 0.